Bài giảng Electrical and electronic principles - Week 1

TRƯỜNG ĐẠI HỌC SƯ PHẠM KỸ THUẬT 
TP. HỒ CHÍ MINH 
ELECTRICAL AND ELECTRONIC 
PRINCIPLES 
WEEK 1 
Cuong Q. Ngo 
CONTENTS 
• INTRODUCTION 
• MULTISIM Software 
• Review: Kirchoff's Current Law(KCL) and Kirchoff's Voltage 
Law (KVL). 
• Circuit analysis 
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INTRODUCTION 
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• Research interest: Signal and Image processing; Machine 
learning. 
• MAIL: cuongnq@hcmute.edu.vn 
• Sites: 
https://sites.google.com/a/hcmute.edu.vn/ngoquoccuong/ 
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1. Starting: MULTISIM 
• Analyses 
Multisim offers you 
many analyses, all of 
which use simulation 
to generate the data 
for the analysis you 
want to perform. 
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Review 
• Branch: represents a single 
element such as a voltage 
source or a 
resistor. 
• Node: the point of 
connection between two or 
more branches. 
• Loop: any closed path in a 
circuit. 
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2. Kirchhoff’s Laws 
• Ohm’s law by itself is not sufficient to 
analyze circuits. 
• Kirchhoff’s laws were first introduced in 
1847 by the German physicist Gustav 
Robert Kirchhoff (1824–1887). 
• 
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2. Kirchhoff’s Laws 
• Kirchhoff’s current law (KCL) states that the algebraic sum of 
currents entering (or leaving) a node (or a closed boundary) 
is zero. 
 where N is the number of branches connected to the node 
and is the nth current entering (or leaving) the node. 
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2. Kirchhoff’s Laws 
• Kirchhoff’s voltage law (KVL) states that the algebraic sum of 
all voltages around a closed path (or loop) is zero. 
• where M is the number of voltages in the loop (or the 
number of branches in the loop) and is the mth voltage. 
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2. Kirchhoff’s Laws 
• Find the voltages v1 and v2 
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Exercise 1.1 
• Find v1 and v2 
• Answer: v1= 16 V; v2= -8 V 
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Exercise 1.2 
• Using MultiSim to solve exercise 1.1 
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Exercise 1.3 
• Find current i0 and voltage v0 in the circuit below 
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Exercise 1.3 
• Solution: 
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Exercise 1.4 
• Find v0 
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Exercise 1.4 
• Using KVL 
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Exercise 1.5 
• Find currents and voltage in the circuit below 
• Answer: 
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Exercise 1.5 
Solution 
• By Ohm’s law: 
 18 
Exercise 1.6 
• Find the currents and voltages in the circuit below 
• Answer: 
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