Bài giảng Phân tích và thiết kế giải thuật - Chương 8: Approximation Algorithms

Tóm tắt Bài giảng Phân tích và thiết kế giải thuật - Chương 8: Approximation Algorithms: ...mal vertex-cover.Then C* must include at least one end of each edge in A and no two edges in A are covered by the same vertex in C*, so |C*||A|. Moreover, |C|=2|A|, so |C|2|C*|.9The Set Covering Problem The set covering problem is an optimization problem that models many resource-selection problem...DY-SET-COVER can easily be implemented to run in time complexity in |X| and |F|. Since the number of iterations of the loop on line 3-6 is at most min(|X|, |F|) and the loop body can be implemented to run in time O(|X|,|F|), there is an implementation that runs in time O(|X|,|F| min(|X|,|F|) .13Rati...le H that visits the vertices in the order of L. /* H is the result to return * /end A preorder tree walk recursively visits every vertex in the tree, listing a vertex when its first encountered, before any of its children are visited.16Thí dụ minh họa giải thuật APPROX-TSP-TOUR17The preorder tree w...

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Chapter 8Approximation Algorithms1OutlineWhy approximation algorithms?The vertex cover problemThe set cover problemTSP2Why Approximation Algorithms ?Many problems of practical significance are NP-complete but are too important to abandon merely because obtaining an optimal solution is intractable. If a problem is NP-complete, we are unlikely to find a polynomial time algorithm for solving it exactly, but it may still be possible to find near-optimal solution in polynomial time. In practice, near-optimality is often good enough. An algorithm that returns near-optimal solutions is called an approximation algorithm.3Performance bounds for approximation algorithmsi is an optimization problem instancec(i) be the cost of solution produced by approximate algorithm and c*(i) be the cost of optimal solution. For minimization problem, we want c(i)/c*(i) to be as small as possible.For maximization problem, we want c*(i)/c(i) to be as small as possible.An approximation algorithm for the given problem instance i, has a ratio bound of p(n) if for any input of size n, the cost c of the solution produced by the approximation algorithm is within a factor of p(n) of the cost c* of  an optimal solution. That is            max(c(i)/c*(i), c*(i)/c(i)) ≤ p(n) 4Note that  p(n) is always greater than or equal to 1. If p(n) = 1 then the approximate algorithm is an optimal algorithm.The larger p(n), the worst algorithmRelative errorWe define the relative error of the approximate algorithm for any input size as |c(i) - c*(i)|/ c*(i)We say that an approximate algorithm has a relative error bound of ε(n) if |c(i)-c*(i)|/c*(i)≤ ε(n)51. The Vertex-Cover ProblemVertex cover: given an undirected graph G=(V,E), then a subset V'V such that if (u,v)E, then uV' or v V' (or both).Size of a vertex cover: the number of vertices in it.Vertex-cover problem: find a vertex-cover of minimal size.This problem is NP-hard, since the related decision problem is NP-complete6Approximate vertex-cover algorithmThe running time of this algorithm is O(E).78Theorem:APPROXIMATE-VERTEX-COVER has a ratio bound of 2, i.e., the size of returned vertex cover set is at most twice of the size of optimal vertex-cover.Proof:It runs in poly timeThe returned C is a vertex-cover.Let A be the set of edges picked in line 4 and C* be the optimal vertex-cover.Then C* must include at least one end of each edge in A and no two edges in A are covered by the same vertex in C*, so |C*||A|. Moreover, |C|=2|A|, so |C|2|C*|.9The Set Covering Problem The set covering problem is an optimization problem that models many resource-selection problems. An instance (X, F) of the set-covering problem consists of a finite set X and a family F of subsets of X, such that every element of X belongs to at least one subset in F: X =  S SF We say that a subset SF covers its elements. The problem is to find a minimum-size subset C  F whose members cover all of X: X =  S SCWe say that any C satisfying the above equation covers X.10Figure 6.2 An instance {X, F} of the set covering problem, where X consists of the 12 black points and F = { S1, S2, S3, S4, S5, S6}. A minimum size set cover is C = { S3, S4, S5}. The greedy algorithm produces the set C’ = {S1, S4, S5, S3} in order.11Applications of Set-covering problemAssume that X is a set of skills that are needed to solve a problem and we have a set of people available to work on it. We wish to form a team, containing as few people as possible, s.t. for every requisite skill in X, there is a member in the team having that skill.Assign emergency stations (fire stations) in a city.Allocate sale branch offices for a company.Schedule for bus drivers.12A greedy approximation algorithmGreedy-Set-Cover(X, F)1. U = X2. C = 3. while U !=  do4. select an SF that maximizes | S  U|5. U = U – S6. C = C  {S}7. return C The algorithm GREEDY-SET-COVER can easily be implemented to run in time complexity in |X| and |F|. Since the number of iterations of the loop on line 3-6 is at most min(|X|, |F|) and the loop body can be implemented to run in time O(|X|,|F|), there is an implementation that runs in time O(|X|,|F| min(|X|,|F|) .13Ratio bound of Greedy-set-coverLet denote the dth harmonic number d hd = i-11/iTheorem: Greedy-set-cover has a ratio bound H(max{|S|: S F})Corollary: Greedy-set-cover has a ratio bound of (ln|X| +1) (Refer to the text book for the proofs) 143. The Traveling Salesman ProblemSince finding the shortest tour for TSP requires so much computation, we may consider to find a tour that is almost as short as the shortest. That is, it may be possible to find near-optimal solution.Example: We can use an approximation algorithm for the HCP. It's relatively easy to find a tour that is longer by at most a factor of two than the optimal tour. The method is based on the algorithm for finding the minimum spanning tree andan observation that it is always cheapest to go directly from a vertex u to a vertex w; going by way of any intermediate stop v can’t be less expensive. C(u,w)  C(u,v)+ C(v,w)15APPROX-TSP-TOURThe algorithm computes a near-optimal tour of an undirected graph G.procedure APPROX-TSP-TOUR(G, c);begin select a vertex r  V[G] to be the “root” vertex; grow a minimum spanning tree T for G from root r, using Prim’s algorithm; apply a preorder tree walk of T and let L be the list of vertices visited in the walk; form the halmintonian cycle H that visits the vertices in the order of L. /* H is the result to return * /end A preorder tree walk recursively visits every vertex in the tree, listing a vertex when its first encountered, before any of its children are visited.16Thí dụ minh họa giải thuật APPROX-TSP-TOUR17The preorder tree walk is not simple tour, since a node be visited many times, but it can be fixed, the tree walk visits the vertices in the order a, b, c, b, h, b, a, d, e, f, e, g, e, d, a. From this order, we can arrive to the hamiltonian cycle H: a, b, c, h, d, e ,f, g, a.18The total cost of H is approximately 19.074. An optimal tour H* has the total cost of approximately 14.715.The running time of APPROX-TSP-TOUR is O(E) = O(V2), since the input graph is a complete graph.The optimal tour19Ratio bound of APPROX-TSP-TOURTheorem: APPROX-TSP-TOUR is an approxima-tion algorithm with a ratio bound of 2 for the TSP with triangle inequality.Proof: Let H* be an optimal tour for a given set of vertices. Since we obtain a spanning tree by deleting any edge from a tour, if T is a minimum spanning tree for the given set of vertices, then c(T)  c(H*) (1)A full walk of T traverses every edge of T twice, we have: c(W) = 2c(T) (2) (1) and (2) imply that: c(W)  2c(H*) (3)20But W is not a tour, since it visits some vertices more than once. By the triangle inequality, we can delete a visit to any vertex from W. By repeatedly applying this operation, we can remove from W all but the first visit to each vertex.Let H be the cycle corresponding to this preorder walk. It is a hamiltonian cycle, since every vertex is visited exactly once. Since H is obtained by deleting vertices from W, we have c(H)  c(W) (4)From (3) and (4), we conclude: c(H)  2c(H*)So, APPROX-TSP-TOUR returns a tour whose cost is not more than twice the cost of an optimal tour.21Appendix: A Taxonomy of Algorithm Design StrategiesStrategy name	 	Examples----------------------------------------------------------------------------------------Bruce-force Sequential search, selection sortDivide-and-conquer	Quicksort, mergesort, binary searchDecrease-and-conquer	Insertion sort, DFS, BFSTransform-and-conquer	heapsort, Gauss eliminationGreedy 	Prim’s, Dijkstra’sDynamic Programming	Floyd’sBacktracking	Branch-and-BoundApproximate algorithmsHeuristics Meta-heuristics22

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